2x^2-16x-64=1832

Solution for 2x^2-16x-64=1832 equation:

2x^2-16x-64=1832

We move all terms to the left:

2x^2-16x-64-(1832)=0

We add all the numbers together, and all the variables

2x^2-16x-1896=0

a = 2; b = -16; c = -1896;
Δ = b2-4ac
Δ = -162-4·2·(-1896)
Δ = 15424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15424}=\sqrt{64*241}=\sqrt{64}*\sqrt{241}=8\sqrt{241}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8\sqrt{241}}{2*2}=\frac{16-8\sqrt{241}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8\sqrt{241}}{2*2}=\frac{16+8\sqrt{241}}{4}
$